With this circuit we can power small appliances which use 9V batteries from the power grid, with a good economy. This circuit is for appliances with currents up to about 50 mA. The advantage of this circuit over many eliminators is in the use of the transformer which provides safety and a zener diode regulation.

 

This circuit uses a 9 + 9 V secondary transformer with current between 50 and 200 mA. The zener diode is 1 W and in the output we must use a connector or plug according to the device to be fed. In Figure 1, we have the complete eliminator circuit.

 

 

Figure 1 - Complete circuit of the eliminator.
Figure 1 - Complete circuit of the eliminator. | Clique na imagem para ampliar |

 

 

The resistor R1 should have a dissipation of 1 W if the consumption of the appliance is high and tends to heat up. Note the polarity of the output connector. In Figure 2, we have the assembly using a terminal strip.

 

Figure 2 - Assembly using a terminal strip
Figure 2 - Assembly using a terminal strip | Clique na imagem para ampliar |

 

 

If the feeding device tends to rumble increase the value of C1.

 

 

 

Material list

 

D1, D2 - 1N4002 or equivalent - silicon diodes

Z1 - 9V1 - 1 W zener diode

T1 - Transformer with primary 110 V or 220 V and secondary of 9 V x 50 to 200 mA

R1- 220 ohms x ½ W- resistor - red, red, brown

C1- 100 uF at 1000 uF x 12 V - electrolytic capacitor

X1- Connector according to the power supply or plug

Miscellaneous: terminal strip, power cable, mounting box, wires, solder, etc.